(x^3/2+y^3/2)(x^3/2-y^3/2)

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Solution for (x^3/2+y^3/2)(x^3/2-y^3/2) equation: 


x in (-oo:+oo)

((x^3)/2+(y^3)/2)*((x^3)/2-((y^3)/2)) = 0

(1/2*x^3+1/2*y^3)*(1/2*x^3-1/2*y^3) = 0

( 1/2*x^3+1/2*y^3 )

1/2*x^3 = -(1/2*y^3) // : 1/2

x^3 = -y^3

x^3 = -y^3 // ^ 1/3

x = y

( 1/2*x^3-1/2*y^3 )

1/2*x^3 = -(-1/2*y^3) // : 1/2

x^3 = y^3

x^3 = y^3 // ^ 1/3

x = y

x in { y, y }

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